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swiftoption-typeunwrap

Swift unwrapping for multiple optionals

I thought this was possible but can't seem to get it to work. I'm sure I'm just being stupid. Im trying to output a formatted address in the form of 

"one, two, three"

from a set of optional components (one, two, three). If "two" is nil then output would be

"one, three" 

let one: String?
let two: String?
let three: String?

one = "one"
two = nil
three = "three"

if let one = one,
        two = two,
        three = three {
     print("\(one),\(two),\(three)")
}
Solution

  • If you're attempting to print the non-nil values as a comma-separated list, then I think @MartinR's suggestion of using flatMap() is the best:

    let one: String?
let two: String?
let three: String?

one = "one"
two = nil
three = "three"

let nonNils = [one, two, three].flatMap { $0 }
if !nonNils.isEmpty {
    print(nonNils.joinWithSeparator(","))
}

    Output:

    one,three