I am trying to wrap a C++ layer over libuv, and using lambda for callback functions. However gcc is erroring out.
Here is the minified version:
#include <uv.h>
class Test {
public:
void on_conn(uv_stream_t *server, int status) { }
void test() {
uv_tcp_t server;
auto err = uv_listen((uv_stream_t*)&server,
100,
[this] (uv_stream_s *server, int status) -> void {
this->on_conn(server,status);
});
}
};
Test t;
The relevant declarations in libuv are:
# define UV_EXTERN /* nothing */
struct uv_stream_s { ... };
typedef struct uv_stream_s uv_stream_t;
typedef void (*uv_connection_cb)(uv_stream_t* server, int status);
UV_EXTERN int uv_listen(uv_stream_t* stream, int backlog, uv_connection_cb cb);
The error g++ is giving:
$ g++ --version
g++ (GCC) 6.1.1 20160501
<<--ERROR--{reformatted}-->>
t.cpp:15:7: error: cannot convert
‘Test::test()::<lambda(uv_stream_s*, int)>’ to
‘uv_connection_cb {aka void (*)(uv_stream_s*, int)}’
for argument ‘3’ to ‘int uv_listen(uv_stream_t*, int, uv_connection_cb)’
}));
What exactly is broken here ? Any way to make this work ?
UPDATE:
More fun .. this in body of lambda does something ; first call works, second doesn't.
int cfunc( void cb() );
class Test {
public:
void d(){}
void test() {
cfunc( [=] () {});
cfunc( [=] () { this->d(); });
//cfunc( [this] () { });
//cfunc( [&this] () { });
}
};
t.cpp:10:34: error: cannot convert ‘Test::test()::<lambda()>’ to ‘void (*)()’ for argument ‘1’ to ‘int cfunc(void (*)())’
cfunc( [=] () { this->d(); });
A capturing lambda cannot be converted to a function pointer, only a non-capturing can:
//Lambda captures 'this', and so cannot be converted to function pointer
[this](uv_stream_s *server, int status) -> void {
this->on_conn(server,status);
}