Is it possible to pass FFMPEG video stream to C# window? Now it opens as new process in new window, I just simply want to pass it to my own SessionWindow. At this moment I execute ffplay like this:
public void ExecuteCommandSync(String command, String args)
{
try
{
System.Diagnostics.ProcessStartInfo procStartInfo =
new System.Diagnostics.ProcessStartInfo("\"" + command + "\"", args);
procStartInfo.RedirectStandardOutput = true;
procStartInfo.UseShellExecute = false;
procStartInfo.CreateNoWindow = true;
System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo = procStartInfo;
proc.Start();
string result = proc.StandardOutput.ReadToEnd();
Debug.WriteLine(result);
}
catch (Exception objException)
{
}
}
private void button2_Click(object sender, EventArgs e)
{
String runPlay = @"C:\FFMPEG\bin\ffplay.exe";
String Random = "udp://127.0.0.1:1234";
this.ExecuteCommandSync(runPlay, Random);
}
PS. I don't want to use Windows Media Player since I want this app to look and work like remote desktop.
Looks like I found answer.
Process ProcFFplay = new Process();
ProcFFplay.StartInfo.FileName = @"C:\FFMPEG\bin\ffplay.exe";
ProcFFplay.StartInfo.Arguments = @"-probesize 32 udp://192.168.88.228:12340";
ProcFFplay.StartInfo.CreateNoWindow = true;
ProcFFplay.StartInfo.RedirectStandardOutput = true;
ProcFFplay.StartInfo.UseShellExecute = false;
ProcFFplay.EnableRaisingEvents = true;
ProcFFplay.OutputDataReceived += (o, k) => Debug.WriteLine(k.Data ?? "NULL", "ffplay");
ProcFFplay.ErrorDataReceived += (o, k) => Debug.WriteLine(k.Data ?? "NULL", "ffplay");
ProcFFplay.Exited += (o, k) => Debug.WriteLine("Exited", "ffplay");
ProcFFplay.Start();
Thread.Sleep(4500);//this is time which you need to wait to get first frames approximately
SetParent(ProcFFplay.MainWindowHandle, this.panel1.Handle);
MoveWindow(ProcFFplay.MainWindowHandle, -5, -30, 1200, 800, true); //these parameteres may look weird but you hide top "stripe" using them.
Enjoy.