write a program that determines if user input is even or odd and loops

Question

I am trying to make a program that will continuously take a user input and determine if the user input is even or odd. The program will only stop when zero is entered.

However, when I enter zero, it prints 0 is an even number followed by All done!. The expected output is just All done!. Here is my code:

def main():
    total = 0
    count = 0

    while True:
        entry=int(input('Enter a number or 0 to quit:'))
        if entry % 2 == 0:
            print (format (entry), 'is an even number.')
        else:
            print (format (entry),'is an odd number.')

        if entry == 0:
            print ('All done!')
            break
main()

Answer 1

If you want to check whether the input is zero before doing anything else, do so. If you want to stop the loop in certain conditions, put the break inside a conditional. Note that count and total were unused. Also, format() with no formatting is redundant.

def main():

    while True:
        entry = int(input('Enter a number or 0 to quit:'))    
        if entry == 0:
            print('All done!')
            break
        if entry % 2 == 0:
            print(entry, 'is an even number.')
        else:
            print(entry, 'is an odd number.')

main()