In Python I am using the RRDTool Python wrapper to store and read values into / from a RRD-Database.
The RRDTool for Python is a wrapper for the C-based source / command-line utility of rrdtool.
After creating a database I want to read out it's header using the python command:
header_info = rrdtool.info('database_file_name.rrd')
which is equal to the command line utility:
rrdtool info database_file_name.rd
and which would print header-infos like that:
filename = "database_file_name.rrd"
rrd_version = 5
...
ds[datasource_identifier_1].index = 0
ds[datasource_identifier_1].type = "GAUGE"
...
ds[datasource_identifier_2].index = 1
ds[datasource_identifier_2].type = "GAUGE"
...
In python the output of the command line tool is wrapped inside a single big dictionary with the following schema:
key: value
"filename" : "database_file_name.rrd"
"ds[datasource_identifier_1].index" : "0"
"ds[datasource_identifier_2].type" : "GAUGE"
I am now trying to figure out how to split up that dictionary so that I could access it like that:
index = dictionary["ds"]["datasource_identifier_1"]["index"]
But I do not have a clue how to do that using python. I would guess this can be done with iteration over the original dictionary and split up those keys using "[","]" and "." as triggers and create a new dictionary then.
How can I do that in Python?
We need to parse the keys to see if they look like ds[some_identifier].type
etc.
def process_dict(dictionary):
import re
rgx = re.compile(r"^(ds)\[(.+?)\]\.(index|type)$")
processed = {}
for k, v in dictionary.items():
# does k have the format ds[some_key].index etc
m = rgx.search(k)
if m:
# create the embedded path
ds, ident, attr = m.groups()
processed.setdefault(ds, {}).setdefault(ident, {})[attr] = v
else:
processed[k] = v
return processed