I use AWS EC2 to run my application "Neural network in art". To send images I deploy a website based on flask + virtualenv + apache. After sending the image on the server starts the script, which print each iteration and I want to store it in out.txt
__init__.py:
#...
def apply_style(image_name, style_name, iterations):
command = ['"python ~/neural_artistic_style/neural_artistic_style.py', \
' --subject ', '/var/www/superapp/superapp/uploads/' + image_name, \
' --style ', '/var/www/superapp/superapp/uploads/' + style_name, \
' --iterations ', iterations, \
' --network ~/neural_artistic_style/imagenet-vgg-verydeep-19.mat"']
str = ''.join(command)
network = Popen(str, shell=True, stdout=PIPE)
stats = []
for out in network.stdout:
stats.append(out)
line = ' '.join(stats)
return line
@app.route('/upload', methods=['GET', 'POST'])
def upload():
if request.method == 'POST':
image = request.files['image']
style = request.files['style']
iterations = request.form['iter']
if file and style:
#Saving images...
result = apply_style(image_name, style_name, iterations)
f = open('out.txt', 'w')
f.write(result)
f.close()
return 'FINISHED'
#...
Well, I can upload image via HTTP without writing result in out.txt, but when I do, apache log shows this:
[Wed Jun 01 ...] [:error] [pid 2360:tid 14...] return self.view_functions[rule.endpoint](**req.view_args)
[Wed Jun 01 ...] [:error] [pid 2360:tid 14...] File "/var/www/superapp/superapp/__init__.py", line 72, in upload
[Wed Jun 01 ...] [:error] [pid 2360:tid 14...] f = open('out.txt', 'w')
[Wed Jun 01 ...] [:error] [pid 2360:tid 14...] IOError: [Errno 13] Permission denied: 'out.txt'
All files in this directory now have 777 permission. When I try to write something using simple script like script.py:
f = open('out.txt', 'w')
f.write('some words')
f.close()
everithing works. But with apache it doesn't. Has anyone any ideas how to fix it?
The problem is that apache runs your code in which will have a different working directory, one which you do not intend to write the file into. You must supply a full path to the file.
f = open('/path/to/my/out.txt', 'w')