How can I send a image by using mosquitto?

Question

I'm trying to send a jpg image using MQTT mosquitto broker(pub and sub) in Raspberry Pi2.

This is my python code pub.py(modified)

import paho.mqtt.client as mqtt

def on_publish(mosq, userdata, mid):
    mosq.disconnect()

client = mqtt.Client()
client.connect("test.mosquitto.org", 1883, 60)
client.on_publish = on_publish

f=open("b.jpg", "rb") #3.7kiB in same folder
fileContent = f.read()
byteArr = bytearray(fileContent)
client.publish("image",byteArr,0)

client.loop_forever()

and it's sub.py(modified)

import paho.mqtt.client as mqtt

def on_connect(client, userdata, rc):
    print("Connect" + str(rc))
    client.subscribe("image") 

def on_message(client, userdata, msg):
    print "Topic : ", msg.topic
    f = open("/tmp/output.jpg", "w")  #there is a output.jpg which is different
    f.write(msg.payload)
    f.close()

client = mqtt.Client()
client.on_connect = on_connect
client.on_message = on_message

client.connect("test.mosquitto.org", 1883, 60)

client.loop_forever()

My python verson is 2.7.9.

After I solved some error, It seems to work but It doesn't.

When I implement the sub.py, It connects successfully so I implement the pub.py in other terminal.

However, There isn't any reaction without connect message which is "Connect with result code 0"

There is no error message so I don't know what my mistake is.

Answer 1

In sub.py you have 2 on_public functions which should be renamed on_connect and on_publish respectively.

In pub.py you need to actually set the on_publish method on the client so it will be called once the publish has been completed.

...
client.connect("test.mosquitto.org", 1883, 60)
client.on_publish = on_public
...

Also as @ralight pointed out in his answer to your previous question, you should change client.loop(5) to client.loop_forever() it will still exit once the message has been sent because of the mosq.disconnect()