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pythonpython-3.xspacesstrip

How to strip all whitespace from string


How do I strip all the spaces in a python string? For example, I want a string like strip my spaces to be turned into stripmyspaces, but I cannot seem to accomplish that with strip():

>>> 'strip my spaces'.strip()
'strip my spaces'

Solution

  • Taking advantage of str.split's behavior with no sep parameter:

    >>> s = " \t foo \n bar "
    >>> "".join(s.split())
    'foobar'
    

    If you just want to remove spaces instead of all whitespace:

    >>> s.replace(" ", "")
    '\tfoo\nbar'
    

    Premature optimization

    Even though efficiency isn't the primary goal—writing clear code is—here are some initial timings:

    $ python -m timeit '"".join(" \t foo \n bar ".split())'
    1000000 loops, best of 3: 1.38 usec per loop
    $ python -m timeit -s 'import re' 're.sub(r"\s+", "", " \t foo \n bar ")'
    100000 loops, best of 3: 15.6 usec per loop
    

    Note the regex is cached, so it's not as slow as you'd imagine. Compiling it beforehand helps some, but would only matter in practice if you call this many times:

    $ python -m timeit -s 'import re; e = re.compile(r"\s+")' 'e.sub("", " \t foo \n bar ")'
    100000 loops, best of 3: 7.76 usec per loop
    

    Even though re.sub is 11.3x slower, remember your bottlenecks are assuredly elsewhere. Most programs would not notice the difference between any of these 3 choices.