I try to make a dummy script for debugging. The script should pass the command and all params to syslog. But when I get a param which has quotes I only get a failure.
#!/bin/sh
set -x
param="$*"
logger -t $0 -p local3.debug "$*"
#logger -t $0 -p local3.debug "$param"
#logger -t $0 -p local3.debug "$(echo "$param")"
#logger -t $0 -p local3.debug "${param//\"/}"
#logger -t $0 -p local3.debug "${param[@]}"
I tryd some variants I found, but nothing works.
# d-iptables -L dkdsdds "ddd"
+ param='-L dkdsdds ddd'
++ echo '-L dkdsdds ddd'
+ logger -t /usr/sbin/d-iptables -p local3.debug '-L dkdsdds ddd'
logger: invalid option -- L
Usage:
logger [options] [message]
Options:
-d, --udp use UDP (TCP is default)
-i, --id log the process ID too
-f, --file <file> log the contents of this file
-h, --help display this help text and exit
-n, --server <name> write to this remote syslog server
-P, --port <number> use this UDP port
-p, --priority <prio> mark given message with this priority
-s, --stderr output message to standard error as well
-t, --tag <tag> mark every line with this tag
-u, --socket <socket> write to this Unix socket
-V, --version output version information and exit
I would suggest you change your script to #!/bin/bash and use
logger -t $0 -p local3.debug -- "$(printf "%q " "$@")"
You need the -- so logger doesn't think the -L is one of its options.