I have a string
(A file location) = "C:\User\Projects\54a2135.tif"
There are several tiff files in the location and I will need to pick them and move them to a different folder.
My difficulty is in getting only the .tif
file . I tried string.match
, string.gsub
, string.find
but unable to achieve that. Is there any advice on how I extract just the .tif
file (In this case 54a2135.tif
) from that string?
To start with, \
is the escape character, so it should be escaped in double/single quoted strings. (The other option is to use the long string [[...]]
)
Then you can use pattern matching:
local path = "C:\\User\\Projects\\54a2135.tif"
print(path:match("[^\\]*$"))
The pattern [^\\]*$
matches any non-backslash characters at the end of the string.
If you like to specify it's a .tif
file, change the pattern to [^\\]*%.tif$