I have an array of double:
double theoretical_distribution[] = {1/21, 2/21, 3/21, 4/21, 5/21, 6/21};
And I am trying to computer it's entropy as:
double entropy = 0;
for (int i = 0; i < sizeof(theoretical_distribution)/sizeof(*theoretical_distribution); i++) {
entropy -= (theoretical_distribution[i] * (log10(theoretical_distribution[i])/log10(arity)));
}
However I am getting NaN, I have checked the part
(theoretical_distribution[i] * (log10(theoretical_distribution[i])/log10(arity)))
And found it to return NaN itself, so I assume it's the culprit, however all it's supposed to be is a simple base conversion of the log? Am I missing some detail about the maths of it?
Why is it evaluating to NaN.
You are passing 0
to the log10
function.
This is because your array theoretical_distribution
is being populated with constant values that result from integer computations, all of which have a denominator larger than the numerator.
You probably intended floating computations, so make at least one of the numerator or denominator a floating constant.