Python itertools.combinations continue from certain value?

Question

I used itertools to generate all combinations or printable ascii chars:

for combo in product('0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&\'()*+,-./:;?@[\\]^_`{|}~ \t\n\r\x0b\x0c', repeat=10):

However, script was interrupted, but i got last sequence string. Is there a way to continue generation values using this string as starting sequence? Thank you.

UPD: I trying to solve some CTF task, by bruteforcing XOR cipher text. Xortool's output:

 2:   11.2%
   5:   15.6%
   7:   11.2%
  10:   18.4%
  15:   9.6%
  18:   6.6%
  20:   12.1%
  25:   5.8%
  30:   5.5%
  40:   4.0%

I can't see other solution now, at lest will try to bf 5-byte keys.

Answer 1

Suppose the last string that was processed started with the character '5'. Then you can ignore all strings that started with previous characters, and set up the iteration like so:

for start in ('567...'):
    for subcombo in product('01234567...', repeat=9):
        yield (start,) + subcombo

However you really can't get through this search space. It's easy to calculate the total number of combinations:

>>> len('0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&\'()*+,-./:;?@[\\]^_`{|}~ \t\n\r\x0b\x0c') ** 10
73742412689492826049L

While even if you could process a billion combinations a second, you wouldn't get close in a year:

>>> 1000000000 * 60 * 60 * 24 * 365
31536000000000000