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pythonpython-2.7python-3.xdatetimepytz

Adding a timedelta of +1 day to a date with pytz in python

I'm trying to add a timedelta of +1 days to my datetime object using:

.timedelta(days=1)

With: 

datetime.now(pytz.timezone('Europe/London')).strftime("%d%m%Y")`

But for some reason, it's not working as it doesn't allow it to be put anywhere in that line.

I've also tried:

GMTDAY = datetime.now(pytz.timezone('Europe/London'))
GMTDAY = str(GMTDAY + timedelta(days=1))
GMTDAY = datetime(int(GMTDAY)).strftime("%d%m%Y")

But that returns:

invalid literal for int() with base 10: '2016-04-28 02:50:52.436000+01:00'

Any idea what I am doing wrong and how to solve it?

EDIT:

It's not a duplicate because this one is specifically about doing it with pytz, it's easy to do it without pytz.

Solution

  • If I interpreted correctly what you are trying to do, try something like:

    GMTDAY = datetime.now(pytz.timezone('Europe/London'))
GMTDAY += timedelta(days=1)
tomorrow = GMTDAY.strftime("%d-%m-%Y")
print(tomorrow)

    Output:

    28-04-2016