Getters And Setters C++

Question

Ok Guys My Question here is simple.. I want to construct a getter and setter for diffrent value type.. Basically function overloading but with getters and setters.. i tried it like this

#include <iostream>;

class Vectors {
public:
    Vectors() {};
    Vectors(int a, int b) {
        x = a, y = b;
    }
    int getX() {
        return x;
    }
    int getY() {
        return y;
    }
    float getX() {
        return (float)x;
    }
    float getY() {
        return (float) y;
    }
     friend Vectors operator+(const Vectors& v1, const Vectors& v2);
     friend Vectors operator/(const Vectors& v1, const Vectors& v2);
protected:
    int x, y;
private:

};

Vectors operator+(const Vectors& v1, const Vectors& v2) {
    Vectors brandNew;
    brandNew.x = v1.x + v2.x;
    brandNew.y = v1.y + v2.y;
    return (brandNew);
};

Vectors operator/(const Vectors& v1, const Vectors& v2) {
    Vectors brandNew(v1.x / v2.x, v1.y/v2.y);
    return brandNew;
}

int main() {
    Vectors v1(2, 3);
    Vectors v2(4, 5);
    Vectors v3;
    v3 = v1 + v2;
    Vectors v4 = v1 / v2;

    std::cout << "VECTOR 4 X : " << v4.getX() << std::endl;
    std::cout << "VECTOR 4 Y : " << v4.getY() << std::endl;

    std::cout << "Vector V3 X : " << v3.getX() << std::endl;
    std::cout << "VECTOR V3 Y : " << v3.getX() << std::endl;
}

But Obviously it said cant do function overloading and the only type diffrent is return type..

Answer 1

There's no way to overload a function without changing the arguments that I'm aware of. You need to either change the function name (call it getXFloat() or something) or just to the cast after calling the function like:

float the_x_value = static_cast<float>(vec.getX());

I would go for the second option.