Promise: Ignore Catch and Return to Chain

Question

Is it possible to ignore a catch and return back to the chain?

promiseA()        // <-- fails with 'missing' reason
  .then(promiseB) // <-- these are not going to run 
  .then(promiseC)
  .catch(function(error, ignore){
     if(error.type == 'missing'){
        ignore()  // <-- ignore the catch and run promiseB and promiseC
     }
  })

Is something like this possible?

Answer 1

Here's the synchronous analogy:

try {
  actionA(); // throws
  actionB(); // skipped
  actionC(); // skipped
} catch (e) {
  // can't resume
}

but you want:

try{
   try {
      actionA(); // throws
   } catch (e) {
      if(error.type !== 'missing'){
         throw error; // abort chain
      }
      // keep going
  }
  actionB(); // executes normally if error type was 'missing'
  actionC();
} catch (e) {
  // handle errors which are not of type 'missing'.
}

Here's the promise version:

asyncActionA()        // <-- fails with 'missing' reason
   .catch(error => {
      if(error.type !== 'missing'){
         throw error; // abort chain. throw is implicit Promise.reject(error); 
      }
      // keep going, implicit: return Promise.resolve();
   })
   .asyncActionB(promiseB) // <-- runs
   .asyncActionC(promiseC)
   .catch(err => {
      // handle errors which are not of type 'missing'.
   });