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Can't fix the error: Object of class DOMNodeList could not be converted to string

I am trying to display XML with all the content but I keep getting this error:

Catchable fatal error: Object of class DOMNodeList could not be converted to string in C:\xampp\htdocs\bollywood\rss1.php on line 43

Please help me understand what I am doing wrong.

XML Code:

  <channel><title>Entertainment News</title>
  <link>http://www.yournewssite.com</link>
   <description>All the latest news and gossip</description>
   <item>
   <title>title!!</title>
  <link>http://www.yournewssite.com</link>
  <description><![CDATA[<img src=http://yourwebsite.com/i.php?k=d88d4e2b336966b538983783230051c width=100 height=100>
  <BR>Backstreet Boys, *NSYNC, 98 Degrees and O-Town boy band members have collaborated on a song to promote their new movie. <BR>]]>
  </description>
  <ContentItem Href="http://yourwebiste.com/i.php?k=d88d4e2b336966b538983783230051c7">
  <MediaType FormalName="Picture" />
  <MimeType FormalName="image/jpg" />
  <Property FormalName="caption" value="Nick Carter" />
  </ContentItem>

And this is my PHP code:

 <?php

 $q=$_GET["q"];


 if($q=="Google") {
 $xml=("google.xml");
 } elseif($q=="b") {
 $xml=("sample.xml");
 }

 $xmlDoc = new DOMDocument();
 $xmlDoc->load($xml);



//get elements from "<channel>"
$channel=$xmlDoc->getElementsByTagName('channel')->item(0);
$channel_title = $channel->getElementsByTagName('title')->item(0)->childNodes->item(0)->nodeValue;
$channel_link = $channel->getElementsByTagName('link')->item(0)->childNodes->item(0)->nodeValue;
$channel_desc = $channel->getElementsByTagName('description')->item(0)->childNodes->item(0)->nodeValue;

//output elements from "<channel>"
echo("<p><a href='" . $channel_link
. "'>" . $channel_title . "</a>");
echo("<br>");
echo($channel_desc . "</p>");

$xpath = new DOMXpath($xmlDoc);
$nodeLists = $xpath->query('ContentItem[@Href=""]');

//get and output "<item>" elements
$x=$xmlDoc->getElementsByTagName('item');
for ($i=0; $i< $x->length; $i++) {

    $item_title=$x->item($i)->getElementsByTagName('title')->item(0)->childNodes->item(0)->nodeValue;
 $item_link=$x->item($i)->getElementsByTagName('link')->item(0)->childNodes->item(0)->nodeValue;
   $item_desc=html_entity_decode($x->item($i)->getElementsByTagName('description')->item(0)->childNodes->item(0)->nodeValue);
    $item_ContentItem=$xpath->$nodeLists->item(0)->childNodes->item(0)->nodeValue;
   echo ("<p><a href=''" . $item_link
  . "'>" . $item_title . "</a>");
  echo ("<br>");
  echo ($item_desc);
  echo ("<br>");
  echo var_dump($item_ContentItem);
  }


  ?>

This is LINE 43, where I keep getting error: 

$item_ContentItem=$xpath->$nodeLists->item(0)->childNodes->item(0)->nodeValue;

Please help, I would really appreciate it.

Solution

  • You have this XML:

    <ContentItem Href="http://yourwebiste.com/i.php?k=d88d4e2b336966b538983783230051c7">
    <MediaType FormalName="Picture" />
    <MimeType FormalName="image/jpg" />
    <Property FormalName="caption" value="Nick Carter" />
</ContentItem>

    This XPath pattern:

    ContentItem[@Href=""]

    search for a <ContentItem> node at first root level (same level of <title>, if the root node is <channel>) with an empty Href attribute: your desired node is not at first root level and doesn't have an empty Href attribute, so your query fails.

    To search for <ContentItem> in any tree position with Href attribute you have to use this pattern:

    //ContentItem[@Href]

    (// means: “search in any position”)

    Then, <ContentItem> has not a node value, and its childnodes are two <MediaType> nodes and one <Property> node (both without node values). Your

    $nodeLists->item(0)->childNodes->item(0)->nodeValue;

    select <MediaType FormalName="Picture" /> and try to extract its node value, an empty string.

    To retrieve the Href attributes, use this syntax:

    $nodeLists = $xpath->query( '//ContentItem[@Href]' );
$item_ContentItem = $nodeLists->item(0)->getAttribute( 'Href' );

    Or — if you want directly select attribute with XPath:

    $item_ContentItem = $xpath->query( '//ContentItem[@Href]/@Href' )->item(0)->nodeValue;