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pythonsubprocessoutputstandards

Python: How to read stdout of subprocess in a nonblocking way


I am trying to make a simple python script that starts a subprocess and monitors its standard output. Here is a snippet from the code:

process = subprocess.Popen([path_to_exe, os.path.join(temp_dir,temp_file)], stdout=subprocess.PIPE)
while True:   
    output=process.stdout.readline()
    print "test"

The problem is that the script hangs on output=process.stdout.readline() and that the line print "test" only executes after the subprocess is terminated.

Is there a way to read standard output and print it without having to wait for the subprocess to terminate?

The subprocess which I am starting is a Windows binary for which I do not have the source code.

I have found several similar questions, but the answers are only applicable on Linux or in case I have the source of the suprocess I am starting.


Solution

  • Check select module

    import subprocess
    import select
    import time
        
    x=subprocess.Popen(['/bin/bash','-c',"while true; do sleep 5; echo yes; done"],stdout=subprocess.PIPE)
        
    y=select.poll()
    y.register(x.stdout,select.POLLIN)
    
    while True:
      if y.poll(1):
         print x.stdout.readline()
      else:
         print "nothing here"
         time.sleep(1)
    

    EDIT:

    Threaded Solution for non posix systems:

    import subprocess
    from threading import Thread 
    import time
     
    linebuffer=[]
    x=subprocess.Popen(['/bin/bash','-c',"while true; do sleep 5; echo yes; done"],stdout=subprocess.PIPE)
    
    def reader(f,buffer):
       while True:
         line=f.readline()
         if line:
            buffer.append(line)
         else:
            break
    
    t=Thread(target=reader,args=(x.stdout,linebuffer))
    t.daemon=True
    t.start()
    
    while True:
      if linebuffer:
         print linebuffer.pop(0)
      else:
         print "nothing here"
         time.sleep(1)