I'm trying to upload an image to a REST webpage. I can do this successfully though a cURL call:
curl -u Admin:admin -T C:\temp\wikiTable.jpg http://192.168.0.35:8080/xwiki/rest/wikis/xwiki/spaces/Main/pages/WebHome/attachments/table.jpg
I'm now trying to achieve this though a HTTP Post in Excel vba but experiencing some problems. I'm currently doing this:
Const STR_BOUNDARY As String = "---------------------------123456789abc"
Dim nFile As Integer
Dim baBuffer() As Byte
Dim sPostData As String
Dim sFileName As String
Dim sUrl As String
sFileName = "C:\temp\wikiTable.jpg"
sUrl = "http://192.168.0.35:8080/xwiki/rest/wikis/xwiki/spaces/Main/pages/WebHome/attachments/table.jpg"
'--- read file
nFile = FreeFile
Open sFileName For Binary Access Read As nFile
If LOF(nFile) > 0 Then
ReDim baBuffer(0 To LOF(nFile) - 1) As Byte
Get nFile, , baBuffer
sPostData = StrConv(baBuffer, vbUnicode)
End If
Close nFile
'-- post
Dim HTTPReq As Object
Set HTTPReq = CreateObject("WinHttp.WinHttpRequest.5.1")
HTTPReq.Option(4) = 13056
HTTPReq.Open "Post", sUrl, False
HTTPReq.SetCredentials "Admin", "admin", 0
HTTPReq.setRequestHeader "Content-Type: multipart/form-data;"
HTTPReq.send sPostData
MsgBox (HTTPReq.responseText)
For the responseText I keep getting the following error:
10.4.6 405 Method Not Allowed
The method specified in the Request-Line is not allowed for the resource
identified by the Request-URI. The response MUST include an Allow header
containing a list of valid methods for the requested resource.
https://www.w3.org/Protocols/rfc2616/rfc2616-sec10.html#sec10.4.6
Any ideas what I'm doing wrong here?
The following worked in the end:
Private Function PostFile(sUrl As String, sFileName As String, strUserName As String, strPassword As String) As String
Dim nFile As Integer
Dim baBuffer() As Byte
Dim sPostData As String
'--- read file
Dim adoStream
Set adoStream = CreateObject("ADODB.Stream")
adoStream.Mode = 3 ' read write
adoStream.Type = 1 ' adTypeBinary
adoStream.Open
adoStream.LoadFromFile (sFileName)
adoStream.Position = 0
'--- post
Dim HTTPReq As Object
Set HTTPReq = CreateObject("WinHttp.WinHttpRequest.5.1")
HTTPReq.Option(4) = 13056
HTTPReq.Open "PUT", sUrl, False
HTTPReq.setRequestHeader "Authorization", "Basic " + Base64Encode(strUserName + ":" + strPassword)
HTTPReq.setRequestHeader "Content-Type", "multipart/form-data"
HTTPReq.setRequestHeader "Content-Length", adoStream.Size
HTTPReq.send (adoStream.Read(adoStream.Size))
pvPostFile = HTTPReq.responseText
Set adoStream = Nothing
End Function