Algorithm for converting octal numbers to decimal?

Question

I have a list of octal numbers that I want to be converted to decimal. Here's my class with what I've done so far:

class Octal:

    #Reads in the file into numberList, converting each line into an int.
    def __init__(self):
        list = []
        file = open("Number Lists/random_numbers3.txt")
        for line in file:
            list.append(int(line))
        self.numberList = list
        file.close()

    #Convert numberList to decimal
    def dec_convert(self):
        decimal = 0
        decimalList = []
        for line in self.numberList:
            temp = str(line)
            i = 0
            while i < len(temp):
                digit = int(temp[i])
                item = (digit * (8 ** (len(temp) - i)))
                decimal = decimal + item
                i += 1

            decimalList.append(decimal)
        return decimalList



    def get_list(self):
        return self.numberList

I read in the numbers from a file, that works fine. But I don't think that my dec_convert() function actually works. It just keeps running and doesn't finish.

It looks completely terrible and hard to read, so I was wondering if there was a simpler way of converting each octal number in the list to a decimal number?

Answer 1

Here is an easy solution that uses the built-in int() constructor rather your dec_convert() function.

class Octal:
    def __init__(self):
        with open("Number Lists/random_numbers3.txt") as fp:
            self.numberList = map(lambda x:int(x,8), fp)
    def get_list(self):
        return self.numberList

if __name__=="__main__":
    o = Octal()
    print(o.get_list())