Moving columns in a bidemensional array in C

Question

Hello I have a bidimensional array initiated the following way:

#include <stdio.h>
#include <stdlib.h>

int main(){

char matriz[6][5]={
{'F','H','V','D','U'},
{'E','L','Q','U','E'},
{'P','E','R','S','E'},
{'V','E','R','A','A'},
{'L','C','A','N','Z'},
{'A','Z','Z','Z','Z'}};

system("pause");
}

And I need to move the columns, ordering alphabetically the first line, I mean, the line that contains {'F','H','V','D','U'}.

I need the following output:

char matriz[6][5]={
{'D','F','H','U','V'},
{'U','E','L','E','Q'},
{'S','P','E','E','R'},
{'A','V','E','A','R'},
{'N','L','C','Z','A'},
{'Z','A','Z','Z','Z'}};

I know I need to use the selective ordering method and a cycle of fors, but I am not sure how.

Answer 1

First you have to compare the first elements of each column to all other top elements,if a column's 1st element is greater than the next column's top element then swap both columns.You can also use qsort function in the algorithm header for sorting.

Below is the implementation:

#include <stdio.h>
int main(){

    int i,k,j;        

    char matriz[6][5]={
    {'F','H','V','D','U'},
    {'E','L','Q','U','E'},
    {'P','E','R','S','E'},
    {'V','E','R','A','A'},
    {'L','C','A','N','Z'},
    {'A','Z','Z','Z','Z'}};

    for(i=0;i<4;i++)
    {
        for(k=i+1;k<5;k++)
        {   
            //comparing top elements of columns 
            if(matriz[0][i]>matriz[0][k])
            {
                //swapping columns
                for(j=0;j<6;j++)
                {
                    int t=matriz[j][i];
                    matriz[j][i]=matriz[j][k];
                    matriz[j][k]=t;
                }
            }
        }
    }

    //display

    for(i=0;i<6;i++)
    {
        for(k=0;k<5;k++)
        printf("%c ",matriz[i][k]);
        printf("\n");
    }

}