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A `find` that returns the condition value, not the element value

I am scanning for an element in source that satisfies a condition. The condition is often, but not always, a regexp match. I'm looking for a version of find that returns the result of the condition, not the original element. With find, I have to re-compute the criterion for the successful element.

The best I worked out runs along this line:

source.find {|e| if (m = e.match(/(e.)/)); break m[0]; end}

To avoid semicolons prompting Rubocop to complain about multi-statement lines, I prefer to write as follows:

source.find {|e| break m[0] if (m = e.match(/(e.)/))}

But Ruby can't cope with the forward reference (and I'm not twisted enough to re-use e for m).

Is there something more elegant to do this job with the short-cutting?

Solution

  • Since you have break, you don't need find to break. Use each.

    source.each {|e| m = e[/e./] and break m}