Determine if file type is ASCII text in bash

I have to sort and print all the file names of files that are ASCII text from a given folder. I made this so far but the file names are printed even if they are PNG images.

#!/bin/bash

for f in $1/*
do
nume=$(basename $f)

if [ 'file $nume'=="$1/$nume: ASCII text" ]; then
    echo $nume
fi
done

Can someone please explain what`s wrong with my code?

Solution

[ wants just an equal sign, not two, and it needs to be separated by spaces (see help test):
```
[ 'file $nume' = "$1/$nume: ASCII text" ]
```
You need $(...) to get the output from a command:
```
[ "$(file $nume)" = "$1/$nume: ASCII text" ]
```
Why are you using basename? file is not going to find your file if you don't give it the whole path:
```
for f in $1/*
do
    if [ "$(file $f)" = "$f: ASCII text" ]; then
        echo $f
    fi
done
```

Always quote your expansions. Quoting can save you a lot of headaches:

for f in "$1"/*
do
    if [ "$(file "$f")" = "$f: ASCII text" ]; then
        echo "$f"
    fi
done

(Optional) Personally, I'd take advantage of [[ and regex matching:
```
if [[ "$(file "$f")" =~ ': ASCII text'$ ]]; then
```