python line break by 10 elements

Question

So I have to write to the standard output 100 number but in a line only put 10 number, I write the code it is almost perfect but the output is like:

23456789101
5378566145 
8353464573 
7596745634 
4352362356 
2342345346 
2553463221 
9873422358 
8223552233 
578942378

and there is the code:

import sys
import random as r

UPTO = 100

def main():
    for i in xrange(UPTO):
        if i % 10 == 0 and i != 0:
            sys.stdout.write(str(r.randint(0, 9)) + '\n')
        else:
            sys.stdout.write(str(r.randint(0, 9))) 
    print

how can I do this perfectly?

Answer 1

You need to start at 1 and go to UPTO + 1:

for i in xrange(1, UPTO + 1):

Once you change that your code works:

In [18]: main()
3989867912
0729456107
3457245171
4564003409
3400380373
1638374598
5290288898
6348789359
4628854868
4172212396

You can also use print as a function with an import from __future__ to simplify your code:

from __future__ import print_function

import random as r

UPTO = 100

def main():
    # use a step of 10
    for i in range(0, UPTO, 10):
        # sep="" will leave no spaces between, end="" removes newline
        print(*(r.randint(0, 9) for _ in range(10)), end="", sep="")
        print()