In code below:
class B {
int x;
int y;
};
class A {
friend class Other;
friend class A;
int a;
B* b;
public:
A(){ b = new B();}
};
struct Other {
A a;
void foo() {
std::cout << a.b->x; // error
}
};
int main() {
Other oth;
oth.foo();
}
The indicated line fails with:
t.cpp:22:19: error: 'x' is a private member of 'B'
std::cout << a.b->x;
^
t.cpp:7:5: note: implicitly declared private here
int x;
Why friendship is not working when referring from class member to other class member?
This line:
std::cout << a.b->x;
involves accessing a private member of A
(b
) and a private member of B
(x
) within class Other
. While A
gave access privileges to Other
, B
did not, hence the error. If you want this to work, you'll need to add:
class B {
friend class Other;
};
Side-note, this declaration is meaningless:
class A {
friend class A;
};
A class already has access to its own private members. So calling it its own friend is redundant.