Consider the following XAML
<ItemsControl ItemsSource="{Binding Path=MyItems, Mode=OneWay, UpdateSourceTrigger=PropertyChanged}" AlternationCount="999" >
<ItemsControl.ItemTemplate>
<DataTemplate>
<StackPanel>
<TextBlock Text="{Binding Path=(ItemsControl.AlternationIndex),
RelativeSource={RelativeSource TemplatedParent},
FallbackValue=FAIL,
StringFormat={}Index is {0}}" />
<ItemsControl ItemsSource="{Binding Path=MySubItems, Mode=OneWay, UpdateSourceTrigger=PropertyChanged}">
<ItemsControl.ItemTemplate>
<DataTemplate>
<StackPanel>
<TextBlock Text="{Binding RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type ItemsControl}, AncestorLevel=1}, Path=(ItemsControl.AlternationIndex)}"/>
<TextBlock Text="{Binding RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type ItemsControl}, AncestorLevel=2}, Path=(ItemsControl.AlternationIndex)}"/>
</StackPanel>
</DataTemplate>
</ItemsControl.ItemTemplate>
</ItemsControl>
</StackPanel>
</DataTemplate>
</ItemsControl.ItemTemplate>
</ItemsControl>
There are three TextBlock nodes. The 1st TextBlock is a direct child of the 1st ItemsControl, and shows the AlternationIndex, as expected. However, I need that AlternationIndex a level deeper, in the second ItemsControl. Therefore I can't use TemplatedParent and thought I could find the Ancestor with AncestorLevel. However, both TextBlock nodes in the 2nd ItemsControl show "0".
What I'm I missing? How do I target the 1st ItemsControl from within the 2nd ItemsControl?
The AlternationIndex won't be on the ItemsControl but on each of its children. Using DataTemplate your ItemsControl will store each children in a ContentPresenter which will have the AlternationIndex. What you need to modify:
<TextBlock Text="{Binding RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type ContentPresenter}, AncestorLevel=2}, Path=(ItemsControl.AlternationIndex)}"/>
<TextBlock Text="{Binding RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type ContentPresenter}, AncestorLevel=2}, Path=(ItemsControl.AlternationIndex)}"/>