Python: easiest way to flatten a tupple containing another tupple from a function

Question

My code is like this:

def f1():
    return 2, 3

def f2():
    return 1, f1()

I can do:

a, (b, c) = f2()

I want to do:

a, b, c = f2()

All the solutions I could find require using a lot of insane parenthesis/brackets, or creating an identity function to use * operator. I would like to only modify f2().

Is there something simpler?

Answer 1

Instead of using 1, f2(), use tuple concatenation:

def f2():
    return (1,) + f1()

As mentioned in a comment, you could also do this:

def f2():
    x,y = f1()
    return 1, x, y

You could also do this:

def f2():
    return (lambda *args: args)(1, *f1())

That is a little long, but it has an advantage over the x,y = f1() solution because this way f1() can return a tuple with any number of elements.