I am newbie to java and JAX-RS.i have developed working example for simple application.
now i want to reduce my url in RESTFul.
Currently i have http://localhost:8084/eshipper_api/apis/api/get_quote
this url.
its working and giving output.
i want to reduce it and want to make it like http://localhost:8084/eshipper_api/apis/get_quote
My web.xml
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
version="3.1">
<servlet>
<servlet-name>Eshipper API Application</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>com.eshipper.client.request</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>Eshipper API Application</servlet-name>
<url-pattern>/apis/*</url-pattern>
</servlet-mapping>
</web-app>
Code in /java/com/eshipper/client/request/RequestHandler.java which is param value for com.eshipper.client.request
@Path("api")
public class RequestHandler
{
@GET
@Path("/get_quote")
public String GetQuote()
{
return "GOdddd Working";
}
}
Please help me for this. Thanks in advance.
Change your @Path("api")
to @Path("")
@Path("")
public class RequestHandler
{
@GET
@Path("/get_quote")
public String GetQuote()
{
return "GOdddd Working";
}
}
Alternatively, you could change your web.xml to:
<url-pattern>/*</url-pattern>
and set your @Path("/apis")
and it would do the same thing.
You have your http://servername/
context/
web.xml servlet path/
class annotated path/
method annotated path