I created a bash script which logs' into a server via telnet. Now I want to cat $var >> /path/on/server/a.log. $var get's specified earlier in the bash script before entering the telnet session. somehow the output "sh: ---------------------------: not found" is created in the telnet session.
I guess that happens because my file.log has multiple lines. the second line is "---------------".
here is my script:
#!/bin/bash
var=$(cat /path/to/local/file.log)
sleep 1
sh << EOF | telnet 192.168.178.72
sleep 2
echo user
sleep 1
echo pass
sleep 5
# echo "$var" >> /path/on/server/file.log (Can't Test because saving the var is not working)
sleep 5
EOF
my final goal is to get file.log onto the server. the only way to connect is via telnet. the client doesn't support ssh or rsync or anything.
edit: more information:
the script doesn'T HAVE to run on the client. I could run it on the server as well. i prefer running the script on the client tho.
I would recommend an approach such as this:
#!/bin/bash
(
echo "telnet 192.168.178.72"
sleep 2
echo user
sleep 1
echo pass
sleep 5
echo "cat >> /path/on/server/file.log"
sleep 5
cat /path/to/local/file.log
) | sh
Note that there is some potential for this to wind up executing the contents of /path/to/local/file.log on the remote server. I would strongly recommend that you consider the security implications of this and perhaps find some better way.