PHP Regex preg_match arguments from a specific function name

Question

Let's say I have

$funcName = 'FooBar';
$myFuncString = $funcName.'("Arg1, Arg2")';

How could I preg_match() so it returns "Arg1, Arg2" (with doubles quotes and without $funcName?

I have tried:

$pattern = '/(?:'.$funcName.'|\".*?)\"/';
preg_match($pattern, myFuncString, $matches);

It returns "Arg1, Arg2" even if $funcName does not match. Any suggestions?

Answer 1

This should work:

$funcName = 'FooBar';
$myFuncString = $funcName.'("Arg1, Arg2")';

//$funcName = 'NooBar';
$pattern = '/'.$funcName.'\("(.*)"\)/';
$matches = preg_match($pattern, $myFuncString, $res);

echo $res[1];

I had to add $res to the preg_match which has the results and correct the pattern.

Demo: http://sandbox.onlinephpfunctions.com/code/6de9d1236b82339199a2c64e914b5ca5b80e4e77