#include <stdio.h>
#include <string.h>
int myprint(char_array){
char mystring[80];
strcat(mystring, "\n");
printf("%s", mystring);
return 0;
}
int main(int argc, char** argv){
int count = 5;
char letter = 'c';
printf("decimal: %d, char: %c\n", count, letter);
myprint("sup");
return 0;
}
I get warnings on compile:
cchilders:~/projects/buildyourownlisp_in_C/ch3 [master]$ compile basics.c basics
basics.c: In function ‘myprint’:
basics.c:4:5: warning: type of ‘char_array’ defaults to ‘int’
int myprint(char_array){
^
It compiles, but my myprint
function doesn't work:
cchilders:~/projects/buildyourownlisp_in_C/ch3 [master]$ ./basics
decimal: 5, char: c
I see this answer warning: return type defaults to ‘int’ [-Wreturn-type] but doesn't apply to me since I did declare int main(...)
I also see this declaration of functions:
return_type function_name( parameter list ) {
body of the function
}
And for myprint
I declare as taking int
and return 0
. What does this warning mean and why doesn't my function work? Thank you
ANSWER:
void myprint(char mystring[]){
strcat(mystring, "\n");
printf("%s", mystring);
}
quiets the warnings, but causes Segmentation fault (core dumped)
Changing to
void myprint(char[] mystring){
strcat(mystring, "\n");
printf("%s", mystring);
}
makes it worse:
cchilders:~/projects/buildyourownlisp_in_C/ch3 [master]$ cc -std=c99 -Wall basics.c -o basics
basics.c:4:21: error: expected ‘;’, ‘,’ or ‘)’ before ‘mystring’
void myprint(char[] mystring;){
^
basics.c: In function ‘main’:
basics.c:15:5: warning: implicit declaration of function ‘myprint’ [-Wimplicit-function-declaration]
myprint("sup");
^
I also tried
void myprint(char[] mystring;){...
and
void myprint(char[] mystring,){...
As others have pointed out, you didn't specify a type for char_array
, so it is assumed to be int
. Changing it to char char_array[]
fixes this.
Your other problem is that you're passing a string constant ("sup"
) to this function and are then attempting to modify it. String constants are stored in a read-only section of memory, so you can't modify it.
Given that you're only printing the string with a newline, you can do this instead:
void myprint(char mystring[]){
printf("%s\n", mystring);
}