where c is a constant
If you unroll the recursion, for the first case you will get:
1^c + 2^c + ... + (n-1)^c + n^c
which is a Faulhaber's formula. It tells you that the complexity is O(n^(c+1))
The second one is:
c^1 + c^2 + ... + c^(n-1) + c^n
which is the sum of geometrics and O(c^n)