I want to run a function independently. From the function I call, I want return without waiting for the other function ending.
I tried with threadind, but this will wait, the end.
thread = threading.Thread(target=myFunc)
thread.daemon = True
thread.start()
return 'something'
Is it possible to return immediately and the other process still run? Thanks for the Answers.
EDITED The working code looks like:
import concurrent.futures
executor = concurrent.futures.ThreadPoolExecutor(2)
executor.submit(myFunc, arg1, arg2)
if I understood your request correctly, you might want to take a look on worker queues https://www.djangopackages.com/grids/g/workers-queues-tasks/
Basically it's not a good idea to offload the work to thread created in view, this is usually handled by having a pool of background workers (processes, threads) and the queue for incoming requests.