I tried to compile the code below with Clang
class Prasoon{
static const int dummy = 0;
};
int const Prasoon::dummy = 0;
int main(){}
The above code did not give any error when compiled with Clang.
prasoon@prasoon-desktop ~ $ clang++ --version
clang version 2.8 (trunk 107611)
Target: i386-pc-linux-gnu
Thread model: posix
prasoon@prasoon-desktop ~ $ cat bug.cpp
class Prasoon{
private:
static const int dummy = 0;
};
int const Prasoon::dummy = 0;
int main(){}
prasoon@prasoon-desktop ~ $ clang++ bug.cpp
prasoon@prasoon-desktop ~ $
But when I compiled the same code with g++
I got an error as expected.
prasoon@prasoon-desktop ~ $ g++ bug.cpp
bug.cpp:8: error: duplicate initialization of ‘Prasoon::dummy’
So have I found a bug in Clang
?
Yes, you have found a bug.
The rule is expressed in the standard:
9.4.2-3: If a static data member is of const literal type, its declaration in the class definition can specify a brace-or- equal-initializer in which every initializer-clause that is an assignment-expression is a constant expression. A static data member of literal type can be declared in the class definition with the constexpr specifier; if so, its declaration shall specify a brace-or-equal-initializer in which every initializer-clause that is an assignment-expression is a constant expression. [ Note: In both these cases, the member may appear in constant expressions. — end note ] The member shall still be defined in a namespace scope if it is used in the program and the namespace scope definition shall not contain an initializer.