Pass row data from model to view in a CodeIgniter application

Question

I have a table menu which consists of (recipe_id,ingredient_id,category_id),ingredient w/c consist of(ingredient_id,name),category(category_id,name) and category_ingredient w/c consist of (ingredient_id,category_id). I want to get all the ingredients of a recipe but my code won't work.

VIEW:

<form method="post">

 <table class="table-responsive table table-hover">
    <tr>        
        <td><strong>Recipe Ingredients</strong></td>
    </tr>
    <?php
    foreach ($products as $product){
        $product_id = $product['recipe_id'];
        ?>
        <tr>    
            <td>
                <?php foreach($this->products_model->getRecipeIngridients($product['recipe_id']) as $ing): ?>
                    <div class="col-sm-10"><li name="ingredients[]" value="<?php echo $ing->ingredient_id ?>" <?php echo (in_array($ing->ingredient_id)) ?>><?php echo $ing->name ?></li></div>
                <?php endforeach; ?>
            </td>
        </tr>
        <?php
    }
    ?>
 </table>
</form>

MODEL:

function getRecipeIngridients($recipe_id)
{
    
    $this->db->where('recipe_id', $recipe_id);
    $query = $this->db->get('menu');
    foreach($query->result() as $row)
    {
        $ingredient_id[] = $row->ingredient_id;
    }

    return $ingredient_id;
}

Answer 1

In getRecipeIngridients() function you are only return ingredient_id not name.

And second issue it that, you are printing ingredient_id as object which is an array in your model function $ingredient_id[] = $row->ingredient_id;

Modified Function:

function getRecipeIngridients($recipe_id)
{
    $this->db->where('recipe_id', $recipe_id);
    $query = $this->db->get('menu');
    $result = $query->result(); // return all data in object form.
    return $result;
}

Code Inside the foreach loop:

<div class="col-sm-10">
<li name="ingredients[]" value="<?php echo $ing->ingredient_id ?>">
    <?php echo $this->db->get_where("ingredient",array("ingredient_id"=>$ing->ingredient_id))->row()->name; ?>
</li>
</div>