Dynamically changing variable name in unix through for loop

Question

Today=$(date)
for i in {2..15}
do
 week_{$i}=$(date -d "$Today +$i week")
 echo ${week_2}
done

I am getting no values in output in BASH.

Answer 1

One way...

    Today=$(date)
    for i in {2..15} 
    do
        tmp=$(date -d "$Today +$i week")
        eval week_${i}=\$tmp
        eval echo  \$week_${i}
    done
    

Second way...

    Today=$(date)
    for i in {2..15} 
    do
        week_[$i]=$(date -d "$Today +$i week")
        echo ${week_[$i]}
    done

Third way...

    Today=$(date)
    for i in {2..15} 
    do
        eval echo \${week_${i}:=$(date -d "$Today +$i week")} > /dev/null
    done

    for i in {2..15} 
    do
        eval echo  \$week_${i}
    done