cmd - export 1 file name to txt

Question

I'm new to scripting so this might be an easy one.

How may I export the name of ONE file in a directory to a text file ? I'm aware dir > text_file.txt will output the list of all files in the directory, however I need this to create a loop which will print every file name individually.

Thanks in advance.

Answer 1

Slightly vague answer for a slightly vague question.

for /r %%G in (*) do echo %%G

to get just, lets say .txt files, use:

for /r %%G in (*.txt) do echo %%G

nicer format if you wish to add more commands:

for /r %%G in (*) do (
    echo Full path : %%G
    echo Name/Ext  : %%~nxG
)

---

EDIT:

Heres a way to do what you mentioned in the comment, echo all files in current directory to a text file:

rem first delete existing output files to clear them.
del full_path.txt >nul
del name_and_ext.txt >nul

for /r %%G in (*) do (
    echo %%G >> full_path.txt
    echo %%~nxG >> name_and_ext.txt
)

Edit this however you please.

Do note;

rem this will override all content in file.txt with !variable!
echo !variable! > file.txt

rem this will add the content of !variable! to new lines accordingly
echo !variable! >> file.txt