Search code examples
csscoordinatesresponsivenessjquery-calculation

calculate position of a point on image in percentage


I am calculating position of a point on a image with the formula below in pixel, where oW is original image width and oH is original image height.

var x = oW * parseInt(document.getElementById('pageX').value - $tagImage.offset().left - 5) / $tagImage.width();

var y = oH * parseInt(document.getElementById('pageY').value - $tagImage.offset().top - 5) / $tagImage.height();

Now, I want to calculate same position in percentage so that the point remains responsive. (Sorry, I am a bit weak in maths so need help)


Solution

  • Once you have the absolute offsets, you just divide by the total width or height (and multiply by 100 to get it as a percentage).

    Here's an example, adapted from this answer.

    $(".test").click(function(e){
      var offset = $(this).offset();
      alert('x = ' + ((e.pageX - offset.left) / $(this).outerWidth() * 100) + "%" );
      alert('y = ' + ((e.pageY - offset.top) / $(this).outerHeight() * 100) + "%" );
    });
    .test {
      width: 200px;
      height: 200px;
      background-color: green;
      margin-left: 50px;
      margin-top: 20px;
    }
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
    <div class="test">
      </div>
    <div>