How to rectify this error class is not key value coding in ios?

Question

I need to iterate the "c"id,"project" id,name in the following JSON response:

    {
      "a": {
        "user": {
          "id": 1,
          "name": "b"
        },
        "startday": "2015-12-27",
        "status": "New",
        "total": 6,
        "c": [
          {
          "id": 768,
          "project": {
            "id": 8,
            "name": "d"
          },
          "user": {
            "id": 1,
            "name": "b"
          },
          "activity": {
            "id": 8,
            "name": "e"
          },
          "hours": 2,
          "comments": "",
          "spent_on": "2015-12-27"
        },
        {
          "id": 775,
          "project": {
            "id": 8,
            "name": "d"
        },
        "user": {
          "id": 1,
          "name": "b"
        },
        "activity": {
          "id": 8,
          "name": "e"
        },
        "hours": 4,
        "comments": "",
        "spent_on": "2015-12-28"
       }
     ]
   }
 }

I've tried

id jsonObjects = [NSJSONSerialization JSONObjectWithData:jsonSource options:NSJSONReadingMutableContainerserror:nil];
NSLog(@"%@",jsonObjects);
if ([jsonObjects objectForKey:@"a"] != [NSNull null]) {
  NSArray *itemArray = [jsonObjects objectForKey:@"a"];
  for (NSDictionary *itemDic in itemArray){
    NSString * user;
    NSArray *user_data =[itemDic valueForKey:@"c"];
    user = [user_data valueForKey:@"id"];
    NSLog(@"%@",user);
  }
}

which throws the error

This class is not key value coding complaint for the key c.

Then I tried

NSDictionary *dictionary =[NSJSONSerializationJSONObjectWithData:jsonSource  options:kNilOptions error:&error];
NSArray * time_entrid = [dictionary valueForKeyPath:@"a.c.id"];
NSLog(@"%@",time_entrid);

How can I solve the error I've mentioned above and iterate properly? Does using the second way enable me to iterate too?

Answer 1

You have One NSArray and NSDictionary For "a" NSDictionary use (you can't iterate NSDictionary only way is)

[[[dictionary objectForKey:@"a"] objectForKey:@"user"] objectForKey:@"id"]

you will get 1, change id by name you will get b

For NSArray

[[[[dictionary objectForKey:@"a"] objectForKey:@"c"] objectAtIndex:0] objectForKey:@"id"]

you will get id 768

For project id

[[[[[dictionary objectForKey:@"a"] objectForKey:@"c"] objectAtIndex:0] objectForKey:@"project"] objectForKey:@"id"]

you will get 8

[[[[[dictionary objectForKey:@"a"] objectForKey:@"c"] objectAtIndex:0] objectForKey:@"project"] objectForKey:@"name"]

you will get name

to iterate array use

for(int i=0; i<[[[dictionary objectForKey:@"a"] objectForKey:@"c"] count];i++)
{

NSLog(@"%@", [[[[dictionary objectForKey:@"a"] objectForKey:@"c"] objectAtIndex:i] objectForKey:@"id"]);
}