I have a simple problem but I can't seem to figure it out because I am new to Maple.
for i from 1 to 1 do
for k from 1 to 4 do
function_table[i][k] := 2*y[i][k]:
function_vector[k] := function_table[i][k]:
od: od:
print(function_vector):
output from print is
table([1 = 2*y[1][1], 2 = 2*y[1][2], 3 = 2*y[1][3], 4 = 2*y[1][4]])
Now what I want to do is take function_vector, and remove the "table index" [1] so I get.
for k from 1 to 4 do
function_vector[k] := 2*y[k]:
od:
print(function_vector):
table([1 = 2*y[1], 2 = 2*y[2], 3 = 2*y[3], 4 = 2*y[4]])
Basically I have the first expression, and I want to convert it to the second example I gave. For example, is there a command or a short way to make y[1][1]
into y[1]
?
Here is one way, that works for your given example at least...
for i from 1 to 1 do
for k from 1 to 4 do
function_table[i][k] := 2*y[i][k]:
function_vector[k] := function_table[i][k]:
end do;
end do:
print(function_vector):
table([1 = 2 y[1][1], 2 = 2 y[1][2], 3 = 2 y[1][3], 4 = 2 y[1][4]])
for x in [indices(function_vector,nolist)] do
new_vector[x]:=subsindets(function_vector[x],indexed,
u->op(0,op(0,u))[op(1,u)]);
end do:
print(new_vector);
table([1 = 2 y[1], 2 = 2 y[2], 3 = 2 y[3], 4 = 2 y[4]])