Here's my code
#include <stdio.h>
#include <conio.h>
int func(int , int);
main(){
int m[3][3]={(0,0,0),
(0,0,0),
(0,0,1)};
int n=3,a;
a=func(m[3][3], n);
if(a==1) printf("True");
else printf ("False");
getch();
}
int func(int m[3][3], int n)
{
int i, j, k=0;
for (i=0;i<n;i++)
for (j=0;j<n;j++)
if(m[i][j]==1) k=1;
return k;
}
Where am I mistaken? The message of the IDE is : Funk.cpp:(.text+0x4b): undefined reference to `func(int, int)' [Error] ld returned 1 exit status
The function prototype and definition of func
doesn't match. Hence the error. Fix it by changing the function prototype to
int func(int[3][3], int);
The next mistake is that this:
a=func(m[3][3], n);
should be changed to
a=func(m, n);
as you want to pass the array, instead of an invalid memory location beyond the array.
And I think that you wanted
int m[3][3]={{0,0,0},
{0,0,0},
{0,0,1}};
instead of
int m[3][3]={(0,0,0),
(0,0,0),
(0,0,1)};
Also, it is better to use a standard definition of main
, i.e, change
main(){
to
int main(void) {