Using qt 5.5, qt quick controls 1.4 and the below qt creator boilerplate code: what is the most FORMAL way to invoke C++ code in response to a button (just debug text to screen)?
// main cpp
#include <QApplication>
#include <QQmlApplicationEngine>
int main(int argc, char *argv[])
{
QApplication app(argc, argv);
QQmlApplicationEngine engine;
engine.load(QUrl(QStringLiteral("qrc:/main.qml")));
return app.exec();
}
and the QML file inside the qml.qrc
:
import QtQuick 2.5
import QtQuick.Controls 1.4
ApplicationWindow {
visible: true
width: 640
height: 480
title: qsTr("Hello World")
Button {
id: add
x: 248
y: 222
text: qsTr("add")
}
}
I am aware of this as a possible answer but it looks a very complicated way to just hook a button to a code! If this is The Formal way to use Qt 5.5 and QML then this should be the answer.
As you can see in the documentation, you have many options:
In your case, I'd prefer the last option because it requires fewer lines of code.
Example:
main.cpp
// main cpp
#include <QGuiApplication>
#include <QQmlApplicationEngine>
#include "myclass.h"
int main(int argc, char *argv[])
{
QGuiApplication app(argc, argv);
QQmlApplicationEngine engine;
engine.load(QUrl(QStringLiteral("qrc:/main.qml")));
QObject *item = engine.rootObjects().first();
MyClass myClass;
QObject::connect(item, SIGNAL(qmlSignal(QString)),
&myClass, SLOT(cppSlot(QString)));
return app.exec();
}
main.qml
import QtQuick 2.5
import QtQuick.Controls 1.4
ApplicationWindow {
visible: true
width: 640
height: 480
title: qsTr("Hello World")
signal qmlSignal(string msg)
Button {
id: add
x: 248
y: 222
text: qsTr("add")
onClicked: qmlSignal(text)
}
}
myclass.h
#ifndef MYCLASS_H
#define MYCLASS_H
#include <QObject>
#include <QDebug>
class MyClass : public QObject
{
Q_OBJECT
public slots:
void cppSlot(const QString &msg) {
qDebug() << "Called the C++ slot with message:" << msg;
}
};
#endif // MYCLASS_H