C++ char array: error while copying data

Question

I have an array:

CHAR m_manuf[256];

I am trying to copy a value to this array as:

m_manuf = "abacus";  //This shows error 

I also tried this variation:

char abc[256] ="abacus";
m_manuf = abc; //Shows error as left value must be l-value

Answer 1

You cant' copy an array like that, instead of you can do,

CHAR    m_manuf[256];
strcpy(m_manuf,"abacus" );

Or

char * m_manuf = "abacus";

Or

char abc[256] ="abacus";
strcpy(m_manuf,abc );

Note : The better way to handle char arrays are using std::string,