I have a cronjob that looks like this:
mysqldump -u XXX -pXXX XXX | gzip -9 > /data/web/xyz123/html/temporary/backup-$(date +%Y%m%d).sql.gz
every time the cronjob is called, the .sql.gz-file is generated. All is good. But I recognized, that the cronjob also generates a file in the root Directory called crontab.php.1, crontab.php.2, crontab.php.3... every time the cronjob is called.
The relevant code in the crontab.php is:
if(!empty($data['set_backup_email'])){
if(sendmail($data['set_backup_email'], 'Backup '.date('Y-m-d'), 'Im Anhang befindet sich das Backup vom '.$day[date('N')].', '.date('d.m.Y').'.', $file, 'backup@abc123.xyz1')){
protocol(61);
unlink($file);
}else{
protocol(62);
send2admin('Das Datenbank-Backup konnte nicht zugestellt werden');
}
}
you are calling php file in the wrong way.
run this command on your linux server
which php
it will give you the path to your php, it will be something like /to/path/php
Add the line in your cron tab as:
* * * * * /to/path/php /filepath/crontab.php
Use *
as per your requirements.
The php file should be on the server.