How i can know how much to be shifted with using shl or shr in assembly.
for example :
0x111111111111116f
To remove the 11111111111111 I will use shl and shr.
mov rsi, 0x111111111111116f
shl rsi, 0x38
shr rsi, 0x38
So, what is the meaning of 0x38 specifically?
How do we know how many bits will be shifted?
So, what is the meaning 0x38 specifically? How do we can know how much will be shifted?
0x38 is a number in the hexadecimal notation. In decimal it represents 56.
shl rsi, 0x38
The value in RSI (whatever it may represent) will be shifted to the left 56 bits.
shr rsi, 0x38
The value in RSI (whatever it may represent) will be shifted to the right 56 bits.