Decrypting zip file encrypted by gpg

Question

When i am trying to decrypt this file in shell using cmd below:

gpg test.zip.asc

After giving the pass I am getting decrypted file "test.zip" in same folder but using python script I am not able to get the decrypted file. No error occurs, any idea on what I'm doing wrong ?

import gnupg

def testgpg():    
    print "testgpg function started"

    encrypted_file = "test.zip.asc"
    passwd = "passwd"
    gpg = gnupg.GPG(gnupghome='/home/centos/.gnupg')
    try:
        print "trying"
        gpg.decrypt(encrypted_file, passphrase=passwd)
        print "decrypted"
    except Exception as e:
        print "not decrypted: -->", str(e)

testgpg()

Answer 1

See the docs for gnupg:

To decrypt a message, use the following approach:
>>> decrypted_data = gpg.decrypt(data)

The module doesn't decrypt the file and save it in the same directory as the original file like the gpg binary. Instead it returns a string of the decrypted data.

However, you also have another problem. gpg.decrypt() is trying to decrypt the value stored in encrpyted_file, which of course is just the string "test.zip.asc". Instead, you want to decrypt the contents of the file with that name. For that, you need to use gpg.decrypt_file() like so:

# Open the encrypted file (gpg will handle reading it)
with open(encrypted_file, 'rb') as src:
    # decrypt the file and store its decrypted contents
    decrypted_contents = gpg.decrypt_file(src, passphrase=passwd)
    # write the decrypted contents to a new file
    with open('destination_file.zip', 'wb') as dst:
        dst.write(decrypted_contents)