How to use NSStringEnumerationOptions.ByWords with punctuation

Question

I'm using this code to find the NSRange and text content of the string contents of a NSTextField.

    nstext.enumerateSubstringsInRange(NSMakeRange(0, nstext.length),
        options: NSStringEnumerationOptions.ByWords, usingBlock: {
            (substring, substringRange, _, _) -> () in
            //Do something with substring and substringRange
    }

The problem is that NSStringEnumerationOptions.ByWords ignores punctuation, so that

Stop clubbing, baby seals

becomes

"Stop" "clubbing" "baby" "seals"

not

"Stop" "clubbing," "baby" "seals

If all else fails I could just check the characters before or after a given word and see if they are on the exempted list (where would I find which characters .ByWords exempts?); but there must be a more elegant solution.

How can I find the NSRanges of a set of words, from a string which includes the punctuation as part of the word?

Answer 1

Inspired by Richa's answer, I used componentsSeparatedByString(" "). I had to add a bit of code to make it work for me, since I wanted the NSRanges from the output. I also wanted it to still work if there were two instances of the same word - e.g. 'please please stop clubbing, baby seals'.

Here's what I did:

            var words:  [String]    = []
            var ranges: [NSRange]   = []

            //nstext is a String I converted to a NSString
            words  = nstext.componentsSeparatedByString(" ")

            //apologies for the poor naming
            var nstextLessWordsWeHaveRangesFor = nstext

            for word in words
            {
                let range:NSRange = nstextLessWordsWeHaveRangesFor.rangeOfString(word)
                ranges.append(range)

                //create a string the same length as word so that the 'ranges' don't change in the future (if I just replace it with "" then the future ranges will be wrong after removing the substring)
                var fillerString:String = ""

                for var i=0;i<word.characters.count;++i{
                   fillerString = fillerString.stringByAppendingString(" ")
                }

                nstextLessWordsWeHaveRangesFor = nstextLessWordsWeHaveRangesFor.stringByReplacingCharactersInRange(range, withString: fillerString)
            }