template < typename T >
class CLASS_TEMPLATE { } ;
template < template < typename T > class CLASS >
void funcI ( ) { }
template void funcI < CLASS_TEMPLATE > () ;
How does compiler instantiate the function, if he does not have any hint about CLASS_TEMPLATE template arguments?
My assumptions about template template were wrong.
Formal template parameter of funcI
is template with one template parameter.
template < template < typename... > class CONTAINER >
void funcII ( )
{
CONTAINER< int > container0 ;
CONTAINER< float > container1 ;
/* ... */
}
template void funcII < std::vector > () ;
will instantiate funcII
template as { std::vector< int > container0 ; std::vector< float > container1 ; /* ... */ }
;
By explicitly instantiating
template void func < CLASS_TEMPLATE > () ;
You are effectively doing this:
template <>
void func<CLASS_TEMPLATE>() { }
There is no need to have the template parameters for CLASS_TEMPLATE
to do that.