This is pretty easy to create with linear-gradient
background images and we don't need more than one div
element to create this with gradients. All we need is a couple of gradient images.
Below is an explanation of how the shape was achieved:
Note: The third bar in the image in question seems to be a little lower than the others, I am assuming this to be an error in the image. If it is not, it could still be achieved with the below approach.
body {
background: yellow;
}
.shape {
height: 100px;
width: 400px;
transform: skew(-30deg);
transform-origin: left bottom;
background-image: linear-gradient(to left, rgba(255,255,255,0.5) 25%, transparent 25%, transparent 33%, rgba(255,255,255,0.75) 33%, rgba(255,255,255,0.5) 60%, transparent 60%, transparent 66%, rgba(255,255,255,1) 66%, rgba(255,255,255,0.75) 93%, transparent 93%), linear-gradient(white, white);
background-size: 15% 100%, 85% 75%;
background-position: 100% 100%, 0% 0%;
background-repeat: no-repeat;
}
<div class='shape'></div>
You could also make use of SVG path
elements to create this shape.
.shape {
position: relative;
height: 100px;
width: 300px;
}
.shape svg {
position: absolute;
height: 100%;
width: 100%;
top: 0px;
left: 0px;
}
.shape svg path#white-bar {
fill: rgba(255, 255, 255, 1);
}
.shape svg path#translucent-bar-1 {
fill: rgba(255, 255, 255, 0.75);
}
.shape svg path#translucent-bar-2 {
fill: rgba(255, 255, 255, 0.5);
}
body {
background: yellow;
}
<div class='shape'>
<svg viewBox='0 0 300 100'>
<path d='M0,75 25,0 240,0, 221.5,75z M245,0 220,100 235,100 260,0' id='white-bar' />
<path d='M265,0 240,100 255,100 280,0' id='translucent-bar-1' />
<path d='M285,0 260,100 275,100 300,0' id='translucent-bar-2' />
</svg>
</div>
Note: It may well be possible to create this using a single path
element and an angled gradient fill but I am not that good with SVG.