How to group the records according to the range in SQL

Question

Hi I would like to create a SQL to group the records according to the range

For example, suppose I have

Number    Time            Price
100    20100810           10.0
100    20100812           15.0
160    20100810           10.0
200    20100810           12.0
210    20100811           13.0
300    20100811           14.0
350    20100810           16.0

Now I need to get the records according to the range of the "Number": [100,200),[200,300),[300,400) and [0,400]. For each range, I need the "Price" of the lastest "Time"

So the results should be

NumberRange         Time            Price
    1            20100812           15.0
    2            20100811           13.0
    3            20100811           14.0
    4            20100812           15.0

How can I construct a SQL statement to produce this?

I am not working on a specific Database. So I am looking for no specific database SQL statement

Answer 1

Use:

 SELECT x.rank, x.time, x.price
   FROM (SELECT *,
                CASE 
                   WHEN number BETWEEN 100 and 199 THEN 1
                   WHEN number BETWEEN 200 and 299 THEN 2
                   WHEN number BETWEEN 300 and 399 THEN 3
                   ELSE NULL
                END AS rank
           FROM TABLE) x
           JOIN (SELECT t.rank,
                        MAX(t.time) AS max_time
                   FROM (SELECT *,
                                CASE 
                                  WHEN number BETWEEN 100 and 199 THEN 1
                                  WHEN number BETWEEN 200 and 299 THEN 2
                                  WHEN number BETWEEN 300 and 399 THEN 3
                                  ELSE NULL
                                END AS rank
                           FROM TABLE) t
               GROUP BY t.rank) y ON y.rank = x.rank 
                                 AND y.max_time = x.time
UNION ALL
SELECT x.rank, x.time, x.price
  FROM (SELECT *,
               CASE 
                 WHEN number BETWEEN 0 and 400 THEN 4
                 ELSE NULL
               END AS rank
          FROM TABLE) x
          JOIN (SELECT t.rank,
                       MAX(t.time) AS max_time
                  FROM (SELECT *,
                               CASE  
                                 WHEN number BETWEEN 0 and 400 THEN 4
                                 ELSE NULL
                               END AS rank
                          FROM TABLE) t
              GROUP BY t.rank) y ON y.rank = x.rank 
                                AND y.max_time = x.time