How to use an extern union array in C?

Question

I want to use a union array similar to that one chux suggested

union {
  uint8_t u8[12];
  uint16_t u16[6];
} *array_u;

array_u = calloc(1, sizeof *array_u);
assert(array_u);

printf("array_u->u8[0] = %" PRIu8 "\n", array_u->u8[0]);

array_u->u16[0] = 1234;
printf("array_u->u16[0] = %" PRIu16 "\n", array_u->u16[0]);
...

Source: Is it okay to store different datatypes in same allocated memory in C?

I want to use it as a global array that different files need to have access to it. So I tried globals.h:

extern union {
    uint8_t u8[12];
    uint16_t u16[6];
} *array_u;

And I want to allocate and free it in this file memory.c:

#include <stdio.h>
#include <stdint.h>
#include <inttypes.h>
#include <stdlib.h>
#include "globals.h"

void allocate_array_u(void){
    array_u = calloc(1, sizeof *array_u);
}

Bud sadly I receive a error LNK2001: unresolved external symbol array_u

How can I fix that?

Solution: I forgot to define the union in main.c or memory.c:

array_u_t *array_u;

Answer 1

In addition to declaring array_u as extern, you also need to define the variable. extern just says to find the definition somewhere else. That definition needs to exist somewhere.

Try the following.

Change globals.h as follows:

typedef union {
    uint8_t u8[12];
    uint16_t u16[6];
} array_u_t;

extern array_u_t *array_u;

Define array_u in memory.c as follows:

#include <stdio.h>
#include <stdint.h>
#include <inttypes.h>
#include <stdlib.h>
#include "globals.h"

array_u_t *array_u; // <---------------- definition

void allocate_array_u(void){
    array_u = calloc(1, sizeof *array_u);
}